6 8Ω speakers in 8Ω impedance?

Given 4 8Ω speakers, I can arrange them to get 8Ω total impedance. But is there a way to combine 6 8Ω speakers to still get 8Ω total impedance? Or is it mathematically not possible? The image has 10 "speakers," because that was the next number I could match 8Ω.