Hey IPMAT Warriors! 💪

With 98 days left, let’s tackle a high-scoring but tricky topic in Quant—Problems on Ages. These questions look simple but can be confusing if you don’t set up equations properly!

📌 Quick Tricks to Solve Age Problems Faster!

🔹 Basic Rule: Always assume the present age as X and form equations based on given conditions.

🔹 Past & Future Age Relation:
If someone’s age was "A years ago", their age back then = (Present Age - A)
If someone’s age will be "A years later", their age then = (Present Age + A)

🔹 Father-Son & Sibling Age Problems:
Look for ratio-based questions! Example: "A father is 4 times his son’s age today. In 10 years, he will be only twice his son’s age. Find their present ages."
✅ Set up the equation:

F=4SF
F+10=2(S+10)

Solve for F (Father's Age) and S (Son's Age).

🔥 Try These Tricky Questions!

1️⃣ Five years ago, a father’s age was seven times his son’s age. Today, the father is three times as old as his son. Find their present ages.

2️⃣ The sum of the ages of a father and son is 50. Five years ago, their age ratio was 7:2. Find their present ages.

3️⃣ A person is twice as old as his friend. 10 years ago, the person was thrice as old as his friend. What are their present ages?

Drop your answers below! Let’s see who gets them right first! 👇🔥Hey IPMAT Warriors! 💪

With 98 days left, let’s tackle a high-scoring but tricky topic in Quant—Problems on Ages. These questions look simple but can be confusing if you don’t set up equations properly!

💬 Struggling with age problems? Comment below & let’s discuss! 👇

Consistency + Smart Practice = IPMAT Success! 🚀

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